Question
Factor the expression
(x+3)(x+4)
Evaluate
x2+7x+12
Rewrite the expression
x2+(4+3)x+12
Calculate
x2+4x+3x+12
Rewrite the expression
x×x+x×4+3x+3×4
Factor out x from the expression
x(x+4)+3x+3×4
Factor out 3 from the expression
x(x+4)+3(x+4)
Solution
(x+3)(x+4)
Show Solution

Find the roots
x1=−4,x2=−3
Evaluate
x2+7x+12
To find the roots of the expression,set the expression equal to 0
x2+7x+12=0
Factor the expression
More Steps

Evaluate
x2+7x+12
Rewrite the expression
x2+(4+3)x+12
Calculate
x2+4x+3x+12
Rewrite the expression
x×x+x×4+3x+3×4
Factor out x from the expression
x(x+4)+3x+3×4
Factor out 3 from the expression
x(x+4)+3(x+4)
Factor out x+4 from the expression
(x+3)(x+4)
(x+3)(x+4)=0
When the product of factors equals 0,at least one factor is 0
x+3=0x+4=0
Solve the equation for x
More Steps

Evaluate
x+3=0
Move the constant to the right-hand side and change its sign
x=0−3
Removing 0 doesn't change the value,so remove it from the expression
x=−3
x=−3x+4=0
Solve the equation for x
More Steps

Evaluate
x+4=0
Move the constant to the right-hand side and change its sign
x=0−4
Removing 0 doesn't change the value,so remove it from the expression
x=−4
x=−3x=−4
Solution
x1=−4,x2=−3
Show Solution
