Question
Solve the quadratic equation
Solve using the quadratic formula
Solve by completing the square
Solve using the PQ formula
x1=5−27,x2=5+27
Alternative Form
x1≈−0.291503,x2≈10.291503
Evaluate
x2−10x−3=0
Substitute a=1,b=−10 and c=−3 into the quadratic formula x=2a−b±b2−4ac
x=210±(−10)2−4(−3)
Simplify the expression
More Steps

Evaluate
(−10)2−4(−3)
Multiply the numbers
More Steps

Evaluate
4(−3)
Multiplying or dividing an odd number of negative terms equals a negative
−4×3
Multiply the numbers
−12
(−10)2−(−12)
Rewrite the expression
102−(−12)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
102+12
Evaluate the power
100+12
Add the numbers
112
x=210±112
Simplify the radical expression
More Steps

Evaluate
112
Write the expression as a product where the root of one of the factors can be evaluated
16×7
Write the number in exponential form with the base of 4
42×7
The root of a product is equal to the product of the roots of each factor
42×7
Reduce the index of the radical and exponent with 2
47
x=210±47
Separate the equation into 2 possible cases
x=210+47x=210−47
Simplify the expression
More Steps

Evaluate
x=210+47
Divide the terms
More Steps

Evaluate
210+47
Rewrite the expression
22(5+27)
Reduce the fraction
5+27
x=5+27
x=5+27x=210−47
Simplify the expression
More Steps

Evaluate
x=210−47
Divide the terms
More Steps

Evaluate
210−47
Rewrite the expression
22(5−27)
Reduce the fraction
5−27
x=5−27
x=5+27x=5−27
Solution
x1=5−27,x2=5+27
Alternative Form
x1≈−0.291503,x2≈10.291503
Show Solution
