Algebra
Calculus
Trigonometry
Matrix
Question
Find the roots
x1=5−215,x2=5+215
Alternative Form
x1≈−2.745967,x2≈12.745967
Evaluate
x2−10x−35
To find the roots of the expression,set the expression equal to 0
x2−10x−35=0
Substitute a=1,b=−10 and c=−35 into the quadratic formula x=2a−b±b2−4ac
x=210±(−10)2−4(−35)
Simplify the expression
More Steps
Evaluate
(−10)2−4(−35)
Multiply the numbers
More Steps
Evaluate
4(−35)
Multiplying or dividing an odd number of negative terms equals a negative
−4×35
Multiply the numbers
−140
(−10)2−(−140)
Rewrite the expression
102−(−140)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
102+140
Evaluate the power
100+140
Add the numbers
240
x=210±240
Simplify the radical expression
More Steps
Evaluate
240
Write the expression as a product where the root of one of the factors can be evaluated
16×15
Write the number in exponential form with the base of 4
42×15
The root of a product is equal to the product of the roots of each factor
42×15
Reduce the index of the radical and exponent with 2
415
x=210±415
Separate the equation into 2 possible cases
x=210+415x=210−415
Simplify the expression
More Steps
Evaluate
x=210+415
Divide the terms
More Steps
Evaluate
210+415
Rewrite the expression
22(5+215)
Reduce the fraction
5+215
x=5+215
x=5+215x=210−415
Simplify the expression
More Steps
Evaluate
x=210−415
Divide the terms
More Steps
Evaluate
210−415
Rewrite the expression
22(5−215)
Reduce the fraction
5−215
x=5−215
x=5+215x=5−215
Solution
x1=5−215,x2=5+215
Alternative Form
x1≈−2.745967,x2≈12.745967
Show Solution
