Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
(x−28)(x+5)
Evaluate
x2−23x−140
Rewrite the expression
x2+(5−28)x−140
Calculate
x2+5x−28x−140
Rewrite the expression
x×x+x×5−28x−28×5
Factor out x from the expression
x(x+5)−28x−28×5
Factor out −28 from the expression
x(x+5)−28(x+5)
Solution
(x−28)(x+5)
Show Solution
Find the roots
x1=−5,x2=28
Evaluate
x2−23x−140
To find the roots of the expression,set the expression equal to 0
x2−23x−140=0
Factor the expression
More Steps
Evaluate
x2−23x−140
Rewrite the expression
x2+(5−28)x−140
Calculate
x2+5x−28x−140
Rewrite the expression
x×x+x×5−28x−28×5
Factor out x from the expression
x(x+5)−28x−28×5
Factor out −28 from the expression
x(x+5)−28(x+5)
Factor out x+5 from the expression
(x−28)(x+5)
(x−28)(x+5)=0
When the product of factors equals 0,at least one factor is 0
x−28=0x+5=0
Solve the equation for x
More Steps
Evaluate
x−28=0
Move the constant to the right-hand side and change its sign
x=0+28
Removing 0 doesn't change the value,so remove it from the expression
x=28
x=28x+5=0
Solve the equation for x
More Steps
Evaluate
x+5=0
Move the constant to the right-hand side and change its sign
x=0−5
Removing 0 doesn't change the value,so remove it from the expression
x=−5
x=28x=−5
Solution
x1=−5,x2=28
Show Solution