Solve x^2-2x^3>0 - ScanMath

Question

Solve the inequality

Solve the inequality by testing the values in the interval

Solve the inequality by separating into cases

x \in (- \infty, 0) \cup (0, \frac{1}{2})

Evaluate

x^{2} - 2 x^{3} > 0

Rewrite the expression

x^{2} - 2 x^{3} = 0

Factor the expression

x^{2} (1 - 2 x) = 0

Separate the equation into 2 possible cases

x^{2} = 0 1 - 2 x = 0

The only way a power can be 0 is when the base equals 0

x = 0 1 - 2 x = 0

Solve the equation

More Steps

x = 0 x = \frac{1}{2}

Determine the test intervals using the critical values

x < 0 0 < x < \frac{1}{2} x > \frac{1}{2}

Choose a value form each interval

x_{1} = - 1 x_{2} = \frac{1}{4} x_{3} = 2

To determine if x < 0 is the solution to the inequality,test if the chosen value x = - 1 satisfies the initial inequality

More Steps

x < 0 is the solution x_{2} = \frac{1}{4} x_{3} = 2

To determine if 0 < x < \frac{1}{2} is the solution to the inequality,test if the chosen value x = \frac{1}{4} satisfies the initial inequality

More Steps

x < 0 is the solution 0 < x < \frac{1}{2} is the solution x_{3} = 2

To determine if x > \frac{1}{2} is the solution to the inequality,test if the chosen value x = 2 satisfies the initial inequality

More Steps

x < 0 is the solution 0 < x < \frac{1}{2} is the solution x > \frac{1}{2} is not a solution

Solution

x \in (- \infty, 0) \cup (0, \frac{1}{2})

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