Question
Solve the quadratic equation
Solve using the quadratic formula
Solve by completing the square
Solve using the PQ formula
x1=−5−25+3,x2=−5+25+3
Alternative Form
x1≈−10.170305,x2≈0.170305
Evaluate
x2−3x3−x=3−x×10
Calculate the product
x2−33×x−x=3−x×10
Use the commutative property to reorder the terms
x2−33×x−x=3−10x
Move the expression to the left side
x2−33×x+9x−3=0
Substitute a=1,b=10 and c=−3 into the quadratic formula x=2a−b±b2−4ac
x=2−10±102−4(−3)
Simplify the expression
More Steps

Evaluate
102−4(−3)
Multiply the numbers
102−(−43)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
102+43
Evaluate the power
100+43
x=2−10±100+43
Simplify the radical expression
More Steps

Evaluate
100+43
Factor the expression
4(25+3)
The root of a product is equal to the product of the roots of each factor
4×25+3
Evaluate the root
More Steps

Evaluate
4
Write the number in exponential form with the base of 2
22
Reduce the index of the radical and exponent with 2
2
225+3
x=2−10±225+3
Separate the equation into 2 possible cases
x=2−10+225+3x=2−10−225+3
Simplify the expression
More Steps

Evaluate
x=2−10+225+3
Divide the terms
More Steps

Evaluate
2−10+225+3
Rewrite the expression
22(−5+25+3)
Reduce the fraction
−5+25+3
x=−5+25+3
x=−5+25+3x=2−10−225+3
Simplify the expression
More Steps

Evaluate
x=2−10−225+3
Divide the terms
More Steps

Evaluate
2−10−225+3
Rewrite the expression
22(−5−25+3)
Reduce the fraction
−5−25+3
x=−5−25+3
x=−5+25+3x=−5−25+3
Solution
x1=−5−25+3,x2=−5+25+3
Alternative Form
x1≈−10.170305,x2≈0.170305
Show Solution
