Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve for x
x>321
Alternative Form
x∈(321,+∞)
Evaluate
x2×x>21
Multiply the terms
More Steps

Evaluate
x2×x
Use the product rule an×am=an+m to simplify the expression
x2+1
Add the numbers
x3
x3>21
Move the expression to the left side
x3−21>0
Rewrite the expression
x3−21=0
Move the constant to the right-hand side and change its sign
x3=0+21
Removing 0 doesn't change the value,so remove it from the expression
x3=21
Take the 3-th root on both sides of the equation
3x3=321
Calculate
x=321
Determine the test intervals using the critical values
x<321x>321
Choose a value form each interval
x1=2x2=4
To determine if x<321 is the solution to the inequality,test if the chosen value x=2 satisfies the initial inequality
More Steps

Evaluate
23>21
Calculate
8>21
Check the inequality
false
x<321 is not a solutionx2=4
To determine if x>321 is the solution to the inequality,test if the chosen value x=4 satisfies the initial inequality
More Steps

Evaluate
43>21
Calculate
64>21
Check the inequality
true
x<321 is not a solutionx>321 is the solution
Solution
x>321
Alternative Form
x∈(321,+∞)
Show Solution
