Question
Simplify the expression
x3−2x2−128x
Evaluate
x3−2x2−8x×16
Solution
x3−2x2−128x
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Factor the expression
x(x2−2x−128)
Evaluate
x3−2x2−8x×16
Multiply the terms
x3−2x2−128x
Rewrite the expression
x×x2−x×2x−x×128
Solution
x(x2−2x−128)
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Find the roots
x1=1−129,x2=0,x3=1+129
Alternative Form
x1≈−10.357817,x2=0,x3≈12.357817
Evaluate
x3−2x2−8x×16
To find the roots of the expression,set the expression equal to 0
x3−2x2−8x×16=0
Multiply the terms
x3−2x2−128x=0
Factor the expression
x(x2−2x−128)=0
Separate the equation into 2 possible cases
x=0x2−2x−128=0
Solve the equation
More Steps

Evaluate
x2−2x−128=0
Substitute a=1,b=−2 and c=−128 into the quadratic formula x=2a−b±b2−4ac
x=22±(−2)2−4(−128)
Simplify the expression
More Steps

Evaluate
(−2)2−4(−128)
Multiply the numbers
(−2)2−(−512)
Rewrite the expression
22−(−512)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
22+512
Evaluate the power
4+512
Add the numbers
516
x=22±516
Simplify the radical expression
More Steps

Evaluate
516
Write the expression as a product where the root of one of the factors can be evaluated
4×129
Write the number in exponential form with the base of 2
22×129
The root of a product is equal to the product of the roots of each factor
22×129
Reduce the index of the radical and exponent with 2
2129
x=22±2129
Separate the equation into 2 possible cases
x=22+2129x=22−2129
Simplify the expression
x=1+129x=22−2129
Simplify the expression
x=1+129x=1−129
x=0x=1+129x=1−129
Solution
x1=1−129,x2=0,x3=1+129
Alternative Form
x1≈−10.357817,x2=0,x3≈12.357817
Show Solution
