Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
x∈(−∞,−1029]∪[1029,+∞)∪{0}
Evaluate
x4−29x2×100≥0
Multiply the terms
x4−2900x2≥0
Rewrite the expression
x4−2900x2=0
Factor the expression
x2(x2−2900)=0
Separate the equation into 2 possible cases
x2=0x2−2900=0
The only way a power can be 0 is when the base equals 0
x=0x2−2900=0
Solve the equation
More Steps

Evaluate
x2−2900=0
Move the constant to the right-hand side and change its sign
x2=0+2900
Removing 0 doesn't change the value,so remove it from the expression
x2=2900
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±2900
Simplify the expression
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Evaluate
2900
Write the expression as a product where the root of one of the factors can be evaluated
100×29
Write the number in exponential form with the base of 10
102×29
The root of a product is equal to the product of the roots of each factor
102×29
Reduce the index of the radical and exponent with 2
1029
x=±1029
Separate the equation into 2 possible cases
x=1029x=−1029
x=0x=1029x=−1029
Determine the test intervals using the critical values
x<−1029−1029<x<00<x<1029x>1029
Choose a value form each interval
x1=−55x2=−27x3=27x4=55
To determine if x<−1029 is the solution to the inequality,test if the chosen value x=−55 satisfies the initial inequality
More Steps

Evaluate
(−55)4−2900(−55)2≥0
Simplify
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Evaluate
(−55)4−2900(−55)2
Multiply the terms
(−55)4−8772500
Calculate
554−8772500
554−8772500≥0
Calculate
378125≥0
Check the inequality
true
x<−1029 is the solutionx2=−27x3=27x4=55
To determine if −1029<x<0 is the solution to the inequality,test if the chosen value x=−27 satisfies the initial inequality
More Steps

Evaluate
(−27)4−2900(−27)2≥0
Simplify
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Evaluate
(−27)4−2900(−27)2
Multiply the terms
(−27)4−2114100
Calculate
274−2114100
274−2114100≥0
Calculate
−1582659≥0
Check the inequality
false
x<−1029 is the solution−1029<x<0 is not a solutionx3=27x4=55
To determine if 0<x<1029 is the solution to the inequality,test if the chosen value x=27 satisfies the initial inequality
More Steps

Evaluate
274−2900×272≥0
Multiply the terms
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Evaluate
2900×272
Evaluate the power
2900×729
Multiply the numbers
2114100
274−2114100≥0
Calculate
−1582659≥0
Check the inequality
false
x<−1029 is the solution−1029<x<0 is not a solution0<x<1029 is not a solutionx4=55
To determine if x>1029 is the solution to the inequality,test if the chosen value x=55 satisfies the initial inequality
More Steps

Evaluate
554−2900×552≥0
Multiply the terms
More Steps

Evaluate
2900×552
Evaluate the power
2900×3025
Multiply the numbers
8772500
554−8772500≥0
Calculate
378125≥0
Check the inequality
true
x<−1029 is the solution−1029<x<0 is not a solution0<x<1029 is not a solutionx>1029 is the solution
The original inequality is a nonstrict inequality,so include the critical value in the solution
x≤−1029 is the solutionx≥1029 is the solutionx=0
Solution
x∈(−∞,−1029]∪[1029,+∞)∪{0}
Show Solution
