Solve x^53=5x 18 - ScanMath

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Type your math problem... x^53=5x 18

Question

Solve the equation

x_{1} = - 430, x_{2} = 0, x_{3} = 430

Alternative Form

x_{1} \approx - 2.340347, x_{2} = 0, x_{3} \approx 2.340347

Evaluate

x^{5} \times 3 = 5 x \times 18

Use the commutative property to reorder the terms

3 x^{5} = 5 x \times 18

Multiply the terms

3 x^{5} = 90 x

Add or subtract both sides

3 x^{5} - 90 x = 0

Factor the expression

3 x (x^{4} - 30) = 0

Divide both sides

x (x^{4} - 30) = 0

Separate the equation into 2 possible cases

x = 0 x^{4} - 30 = 0

Solve the equation

More Steps

Evaluate

x^{4} - 30 = 0

Move the constant to the right-hand side and change its sign

x^{4} = 0 + 30

Removing 0 doesn't change the value,so remove it from the expression

x^{4} = 30

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm 430

Separate the equation into 2 possible cases

x = 430 x = - 430

x = 0 x = 430 x = - 430

Solution

x_{1} = - 430, x_{2} = 0, x_{3} = 430

Alternative Form

x_{1} \approx - 2.340347, x_{2} = 0, x_{3} \approx 2.340347

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