Question
Solve the quadratic equation
Solve by factoring
Solve using the quadratic formula
Solve by completing the square
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x1=−3,x2=21
Alternative Form
x1=−3,x2=0.5
Evaluate
x(2x+5)=3
Expand the expression
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Evaluate
x(2x+5)
Apply the distributive property
x×2x+x×5
Multiply the terms
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Evaluate
x×2x
Use the commutative property to reorder the terms
2x×x
Multiply the terms
2x2
2x2+x×5
Use the commutative property to reorder the terms
2x2+5x
2x2+5x=3
Move the expression to the left side
2x2+5x−3=0
Factor the expression
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Evaluate
2x2+5x−3
Rewrite the expression
2x2+(−1+6)x−3
Calculate
2x2−x+6x−3
Rewrite the expression
x×2x−x+3×2x−3
Factor out x from the expression
x(2x−1)+3×2x−3
Factor out 3 from the expression
x(2x−1)+3(2x−1)
Factor out 2x−1 from the expression
(x+3)(2x−1)
(x+3)(2x−1)=0
When the product of factors equals 0,at least one factor is 0
2x−1=0x+3=0
Solve the equation for x
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Evaluate
2x−1=0
Move the constant to the right-hand side and change its sign
2x=0+1
Removing 0 doesn't change the value,so remove it from the expression
2x=1
Divide both sides
22x=21
Divide the numbers
x=21
x=21x+3=0
Solve the equation for x
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Evaluate
x+3=0
Move the constant to the right-hand side and change its sign
x=0−3
Removing 0 doesn't change the value,so remove it from the expression
x=−3
x=21x=−3
Solution
x1=−3,x2=21
Alternative Form
x1=−3,x2=0.5
Show Solution
