Question
Solve the equation
Solve for x
Solve for b
x=−b+1
Evaluate
x(3−2b)−1=x(2−3b)−b2
Rewrite the expression
(3−2b)x−1=(2−3b)x−b2
Move the expression to the left side
(3−2b)x−1−(2−3b)x=−b2
Move the expression to the right side
(3−2b)x−(2−3b)x=−b2+1
Add and subtract
More Steps

Evaluate
(3−2b)x−(2−3b)x
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
(3−2b)x+(−2+3b)x
Collect like terms by calculating the sum or difference of their coefficients
(3−2b−2+3b)x
Calculate the sum or difference
More Steps

Evaluate
3−2b−2+3b
Subtract the numbers
1−2b+3b
Add the terms
1+b
(1+b)x
(1+b)x=−b2+1
Divide both sides
1+b(1+b)x=1+b−b2+1
Divide the numbers
x=1+b−b2+1
Solution
More Steps

Evaluate
1+b−b2+1
Rewrite the expression
1+b(b+1)(−b+1)
Rewrite the expression
b+1(b+1)(−b+1)
Reduce the fraction
−b+1
x=−b+1
Show Solution
