Solve x(x^2 6x 9)=4(x^3)

Evaluate

x (x^{2} \times 6 x \times 9) = 4 x^{3}

Remove the parentheses

x \times x^{2} \times 6 x \times 9 = 4 x^{3}

Multiply

More Steps

54 x^{4} = 4 x^{3}

Add or subtract both sides

54 x^{4} - 4 x^{3} = 0

Factor the expression

2 x^{3} (27 x - 2) = 0

Divide both sides

x^{3} (27 x - 2) = 0

Separate the equation into 2 possible cases

x^{3} = 0 27 x - 2 = 0

The only way a power can be 0 is when the base equals 0

x = 0 27 x - 2 = 0

Solve the equation

More Steps

x = 0 x = \frac{2}{27}

Solution

x_{1} = 0, x_{2} = \frac{2}{27}

Alternative Form

x_{1} = 0, x_{2} = 0. \dot{0} 7 \dot{4}

Solve the equation