Solve x-3 ≤ 97x

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Type your math problem... x-3 ≤ 97x

Question

Solve the inequality

x \geq - \frac{1}{32}

Alternative Form

x \in [- \frac{1}{32}, + \infty)

Evaluate

x - 3 \leq 97 x

Move the variable to the left side

x - 3 - 97 x \leq 0

Subtract the terms

More Steps

Evaluate

x - 97 x

Collect like terms by calculating the sum or difference of their coefficients

(1 - 97) x

Subtract the numbers

- 96 x

- 96 x - 3 \leq 0

Move the constant to the right side

- 96 x \leq 0 + 3

Removing 0 doesn't change the value,so remove it from the expression

- 96 x \leq 3

Change the signs on both sides of the inequality and flip the inequality sign

96 x \geq - 3

Divide both sides

\frac{96 x}{96} \geq \frac{- 3}{96}

Divide the numbers

x \geq \frac{- 3}{96}

Solution

More Steps

Evaluate

\frac{- 3}{96}

Cancel out the common factor 3

\frac{- 1}{32}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

- \frac{1}{32}

x \geq - \frac{1}{32}

Alternative Form

x \in [- \frac{1}{32}, + \infty)

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