Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
Solve for x
Solve for y
x=y+1
Evaluate
y÷1−(2×yy)+3=x
Simplify
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Evaluate
y÷1−(2×yy)+3
Divide the terms
y÷1−(2×1)+3
Any expression multiplied by 1 remains the same
y÷1−2+3
Divide the terms
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Evaluate
y÷1
Rewrite the expression
1y
Divide the terms
y
y−2+3
Add the numbers
y+1
y+1=x
Solution
x=y+1
Show Solution
Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
y÷1−(2×yy)+3=x
Simplify
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Evaluate
y÷1−(2×yy)+3
Divide the terms
y÷1−(2×1)+3
Any expression multiplied by 1 remains the same
y÷1−2+3
Divide the terms
More Steps
Evaluate
y÷1
Rewrite the expression
1y
Divide the terms
y
y−2+3
Add the numbers
y+1
y+1=x
To test if the graph of y+1=x is symmetry with respect to the origin,substitute -x for x and -y for y
−y+1=−x
Solution
Not symmetry with respect to the origin
Show Solution
Rewrite the equation
r=−sin(θ)−cos(θ)1
Evaluate
y÷1−(2×yy)+3=x
Evaluate
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Evaluate
y÷1−(2×yy)+3
Divide the terms
y÷1−(2×1)+3
Any expression multiplied by 1 remains the same
y÷1−2+3
Divide the terms
More Steps
Evaluate
y÷1
Rewrite the expression
1y
Divide the terms
y
y−2+3
Add the numbers
y+1
y+1=x
Move the expression to the left side
y+1−x=0
To convert the equation to polar coordinates,substitute x for rcos(θ) and y for rsin(θ)
sin(θ)×r+1−cos(θ)×r=0
Factor the expression
(sin(θ)−cos(θ))r+1=0
Subtract the terms
(sin(θ)−cos(θ))r+1−1=0−1
Evaluate
(sin(θ)−cos(θ))r=−1
Solution
r=−sin(θ)−cos(θ)1
Show Solution
Find the first derivative
Find the derivative with respect to x
Find the derivative with respect to y
dxdy=1
Calculate
y:1−(2×yy)+3=x
Simplify the expression
y+1=x
Take the derivative of both sides
dxd(y+1)=dxd(x)
Calculate the derivative
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Evaluate
dxd(y+1)
Use differentiation rules
dxd(y)+dxd(1)
Evaluate the derivative
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Evaluate
dxd(y)
Use differentiation rules
dyd(y)×dxdy
Use dxdxn=nxn−1 to find derivative
dxdy
dxdy+dxd(1)
Use dxd(c)=0 to find derivative
dxdy+0
Evaluate
dxdy
dxdy=dxd(x)
Solution
dxdy=1
Show Solution
Find the second derivative
Find the second derivative with respect to x
Find the second derivative with respect to y
dx2d2y=0
Calculate
y:1−(2×yy)+3=x
Simplify the expression
y+1=x
Take the derivative of both sides
dxd(y+1)=dxd(x)
Calculate the derivative
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Evaluate
dxd(y+1)
Use differentiation rules
dxd(y)+dxd(1)
Evaluate the derivative
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Evaluate
dxd(y)
Use differentiation rules
dyd(y)×dxdy
Use dxdxn=nxn−1 to find derivative
dxdy
dxdy+dxd(1)
Use dxd(c)=0 to find derivative
dxdy+0
Evaluate
dxdy
dxdy=dxd(x)
Use dxdxn=nxn−1 to find derivative
dxdy=1
Take the derivative of both sides
dxd(dxdy)=dxd(1)
Calculate the derivative
dx2d2y=dxd(1)
Solution
dx2d2y=0
Show Solution