Solve y= (1)/x c - ScanMath

Evaluate

y = \frac{1}{x} \times c

Multiply the terms

y = \frac{c}{x}

Find the first partial derivative by treating the variable x as a constant and differentiating with respect to c

\frac{\partial y}{\partial c} = \frac{\partial}{\partial c} (\frac{c}{x})

Use differentiation rule \frac{\partial}{\partial x} (\frac{f ( x )}{g ( x )}) = \frac{\frac{\partial}{\partial x} ( f ( x )) \times g ( x ) - f ( x ) \times \frac{\partial}{\partial x} ( g ( x ) )}{( g ( x ) ) ^{2}}

\frac{\partial y}{\partial c} = \frac{\frac{\partial}{\partial c} ( c ) x - c \times \frac{\partial}{\partial c} ( x )}{x ^{2}}

Use \frac{\partial}{\partial x} x^{n} = n x^{n - 1} to find derivative

\frac{\partial y}{\partial c} = \frac{1 \times x - c \times \frac{\partial}{\partial c} ( x )}{x ^{2}}

Use \frac{\partial}{\partial x} (c) = 0 to find derivative

\frac{\partial y}{\partial c} = \frac{1 \times x - c \times 0}{x ^{2}}

Any expression multiplied by 1 remains the same

\frac{\partial y}{\partial c} = \frac{x - c \times 0}{x ^{2}}

Any expression multiplied by 0 equals 0

\frac{\partial y}{\partial c} = \frac{x - 0}{x ^{2}}

Removing 0 doesn't change the value,so remove it from the expression

\frac{\partial y}{\partial c} = \frac{x}{x ^{2}}

Solution

More Steps

\frac{\partial y}{\partial c} = \frac{1}{x}

Function