Question
y=b×0+b×1×x
Function
Find the first partial derivative with respect to b
Find the first partial derivative with respect to x
∂b∂y=x
Evaluate
y=b×0+b×1×x
Simplify
More Steps

Evaluate
b×0+b×1×x
Any expression multiplied by 0 equals 0
0+b×1×x
Multiply the terms
0+bx
Removing 0 doesn't change the value,so remove it from the expression
bx
y=bx
Find the first partial derivative by treating the variable x as a constant and differentiating with respect to b
∂b∂y=∂b∂(bx)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
∂b∂y=x×∂b∂(b)
Use ∂x∂xn=nxn−1 to find derivative
∂b∂y=x×1
Solution
∂b∂y=x
Show Solution

Solve the equation
Solve for x
Solve for b
Solve for y
x=by
Evaluate
y=b×0+b×1×x
Simplify
More Steps

Evaluate
b×0+b×1×x
Any expression multiplied by 0 equals 0
0+b×1×x
Multiply the terms
0+bx
Removing 0 doesn't change the value,so remove it from the expression
bx
y=bx
Swap the sides of the equation
bx=y
Divide both sides
bbx=by
Solution
x=by
Show Solution
