Question
Function
Find the first partial derivative with respect to l
Find the first partial derivative with respect to x
∂l∂y=31x−31
Evaluate
y=l×31x−31l
Use the commutative property to reorder the terms
y=31lx−31l
Find the first partial derivative by treating the variable x as a constant and differentiating with respect to l
∂l∂y=∂l∂(31lx−31l)
Use differentiation rule ∂x∂(f(x)±g(x))=∂x∂(f(x))±∂x∂(g(x))
∂l∂y=∂l∂(31lx)−∂l∂(31l)
Evaluate
More Steps

Evaluate
∂l∂(31lx)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
31x×∂l∂(l)
Use ∂x∂xn=nxn−1 to find derivative
31x×1
Multiply the terms
31x
∂l∂y=31x−∂l∂(31l)
Solution
More Steps

Evaluate
∂l∂(31l)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
31×∂l∂(l)
Use ∂x∂xn=nxn−1 to find derivative
31×1
Multiply the terms
31
∂l∂y=31x−31
Show Solution

Solve the equation
Solve for x
Solve for l
Solve for y
x=l3y+l
Evaluate
y=l×31x−31l
Use the commutative property to reorder the terms
y=31lx−31l
Swap the sides of the equation
31lx−31l=y
Move the expression to the right-hand side and change its sign
31lx=y+31l
Divide both sides
31l31lx=31ly+31l
Divide the numbers
x=31ly+31l
Solution
More Steps

Evaluate
31ly+31l
Rewrite the expression
31l33y+l
Multiply by the reciprocal
33y+l×l3
Reduce the numbers
(3y+l)×l1
Calculate the product
l3y+l
x=l3y+l
Show Solution
