Question
Function
Find the first partial derivative with respect to p
Find the first partial derivative with respect to g
∂p∂y=g1
Simplify
y=gp
Find the first partial derivative by treating the variable g as a constant and differentiating with respect to p
∂p∂y=∂p∂(gp)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂p∂y=g2∂p∂(p)g−p×∂p∂(g)
Use ∂x∂xn=nxn−1 to find derivative
∂p∂y=g21×g−p×∂p∂(g)
Use ∂x∂(c)=0 to find derivative
∂p∂y=g21×g−p×0
Any expression multiplied by 1 remains the same
∂p∂y=g2g−p×0
Any expression multiplied by 0 equals 0
∂p∂y=g2g−0
Removing 0 doesn't change the value,so remove it from the expression
∂p∂y=g2g
Solution
More Steps

Evaluate
g2g
Use the product rule aman=an−m to simplify the expression
g2−11
Reduce the fraction
g1
∂p∂y=g1
Show Solution

Solve the equation
Solve for g
Solve for p
g=yp
Evaluate
y=gp
Swap the sides of the equation
gp=y
Cross multiply
p=gy
Simplify the equation
p=yg
Swap the sides of the equation
yg=p
Divide both sides
yyg=yp
Solution
g=yp
Show Solution
