Question
Function
Find the vertex
Find the axis of symmetry
Rewrite in vertex form
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(4,−26)
Evaluate
y=x2−8x−10
Find the x-coordinate of the vertex by substituting a=1 and b=−8 into x = −2ab
x=−2×1−8
Solve the equation for x
x=4
Find the y-coordinate of the vertex by evaluating the function for x=4
y=42−8×4−10
Calculate
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Evaluate
42−8×4−10
Multiply the numbers
42−32−10
Evaluate the power
16−32−10
Subtract the numbers
−26
y=−26
Solution
(4,−26)
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Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
y=x2−8x−10
To test if the graph of y=x2−8x−10 is symmetry with respect to the origin,substitute -x for x and -y for y
−y=(−x)2−8(−x)−10
Simplify
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Evaluate
(−x)2−8(−x)−10
Multiply the numbers
(−x)2+8x−10
Rewrite the expression
x2+8x−10
−y=x2+8x−10
Change the signs both sides
y=−x2−8x+10
Solution
Not symmetry with respect to the origin
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Identify the conic
Find the standard equation of the parabola
Find the vertex of the parabola
Find the focus of the parabola
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(x−4)2=y+26
Evaluate
y=x2−8x−10
Swap the sides of the equation
x2−8x−10=y
Move the constant to the right-hand side and change its sign
x2−8x=y−(−10)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
x2−8x=y+10
To complete the square, the same value needs to be added to both sides
x2−8x+16=y+10+16
Use a2−2ab+b2=(a−b)2 to factor the expression
(x−4)2=y+10+16
Solution
(x−4)2=y+26
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Solve the equation
x=4+26+yx=4−26+y
Evaluate
y=x2−8x−10
Swap the sides of the equation
x2−8x−10=y
Move the expression to the left side
x2−8x−10−y=0
Substitute a=1,b=−8 and c=−10−y into the quadratic formula x=2a−b±b2−4ac
x=28±(−8)2−4(−10−y)
Simplify the expression
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Evaluate
(−8)2−4(−10−y)
Multiply the terms
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Evaluate
4(−10−y)
Apply the distributive property
−4×10−4y
Multiply the numbers
−40−4y
(−8)2−(−40−4y)
Rewrite the expression
82−(−40−4y)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
82+40+4y
Evaluate the power
64+40+4y
Add the numbers
104+4y
x=28±104+4y
Simplify the radical expression
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Evaluate
104+4y
Factor the expression
4(26+y)
The root of a product is equal to the product of the roots of each factor
4×26+y
Evaluate the root
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Evaluate
4
Write the number in exponential form with the base of 2
22
Reduce the index of the radical and exponent with 2
2
226+y
x=28±226+y
Separate the equation into 2 possible cases
x=28+226+yx=28−226+y
Simplify the expression
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Evaluate
x=28+226+y
Divide the terms
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Evaluate
28+226+y
Rewrite the expression
22(4+26+y)
Reduce the fraction
4+26+y
x=4+26+y
x=4+26+yx=28−226+y
Solution
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Evaluate
x=28−226+y
Divide the terms
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Evaluate
28−226+y
Rewrite the expression
22(4−26+y)
Reduce the fraction
4−26+y
x=4−26+y
x=4+26+yx=4−26+y
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Rewrite the equation
r=2cos2(θ)sin(θ)+8cos(θ)−1+103cos2(θ)+8sin(2θ)r=2cos2(θ)sin(θ)+8cos(θ)+1+103cos2(θ)+8sin(2θ)
Evaluate
y=x2−8x−10
Move the expression to the left side
y−x2+8x=−10
To convert the equation to polar coordinates,substitute x for rcos(θ) and y for rsin(θ)
sin(θ)×r−(cos(θ)×r)2+8cos(θ)×r=−10
Factor the expression
−cos2(θ)×r2+(sin(θ)+8cos(θ))r=−10
Subtract the terms
−cos2(θ)×r2+(sin(θ)+8cos(θ))r−(−10)=−10−(−10)
Evaluate
−cos2(θ)×r2+(sin(θ)+8cos(θ))r+10=0
Solve using the quadratic formula
r=−2cos2(θ)−sin(θ)−8cos(θ)±(sin(θ)+8cos(θ))2−4(−cos2(θ))×10
Simplify
r=−2cos2(θ)−sin(θ)−8cos(θ)±1+103cos2(θ)+8sin(2θ)
Separate the equation into 2 possible cases
r=−2cos2(θ)−sin(θ)−8cos(θ)+1+103cos2(θ)+8sin(2θ)r=−2cos2(θ)−sin(θ)−8cos(θ)−1+103cos2(θ)+8sin(2θ)
Use b−a=−ba=−ba to rewrite the fraction
r=2cos2(θ)sin(θ)+8cos(θ)−1+103cos2(θ)+8sin(2θ)r=−2cos2(θ)−sin(θ)−8cos(θ)−1+103cos2(θ)+8sin(2θ)
Solution
r=2cos2(θ)sin(θ)+8cos(θ)−1+103cos2(θ)+8sin(2θ)r=2cos2(θ)sin(θ)+8cos(θ)+1+103cos2(θ)+8sin(2θ)
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