Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
y2(1−5y2)
Evaluate
y2−5y4
Rewrite the expression
y2−y2×5y2
Solution
y2(1−5y2)
Show Solution
Find the roots
y1=−55,y2=0,y3=55
Alternative Form
y1≈−0.447214,y2=0,y3≈0.447214
Evaluate
y2−5y4
To find the roots of the expression,set the expression equal to 0
y2−5y4=0
Factor the expression
y2(1−5y2)=0
Separate the equation into 2 possible cases
y2=01−5y2=0
The only way a power can be 0 is when the base equals 0
y=01−5y2=0
Solve the equation
More Steps
Evaluate
1−5y2=0
Move the constant to the right-hand side and change its sign
−5y2=0−1
Removing 0 doesn't change the value,so remove it from the expression
−5y2=−1
Change the signs on both sides of the equation
5y2=1
Divide both sides
55y2=51
Divide the numbers
y2=51
Take the root of both sides of the equation and remember to use both positive and negative roots
y=±51
Simplify the expression
More Steps
Evaluate
51
To take a root of a fraction,take the root of the numerator and denominator separately
51
Simplify the radical expression
51
Multiply by the Conjugate
5×55
When a square root of an expression is multiplied by itself,the result is that expression
55
y=±55
Separate the equation into 2 possible cases
y=55y=−55
y=0y=55y=−55
Solution
y1=−55,y2=0,y3=55
Alternative Form
y1≈−0.447214,y2=0,y3≈0.447214
Show Solution