Question
Function
Find the x-intercept/zero
Find the y-intercept
x1=−210,x2=210
Evaluate
y−5=−2(x×1)2
To find the x-intercept,set y=0
0−5=−2(x×1)2
Removing 0 doesn't change the value,so remove it from the expression
−5=−2(x×1)2
Any expression multiplied by 1 remains the same
−5=−2x2
Swap the sides of the equation
−2x2=−5
Change the signs on both sides of the equation
2x2=5
Divide both sides
22x2=25
Divide the numbers
x2=25
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±25
Simplify the expression
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Evaluate
25
To take a root of a fraction,take the root of the numerator and denominator separately
25
Multiply by the Conjugate
2×25×2
Multiply the numbers
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Evaluate
5×2
The product of roots with the same index is equal to the root of the product
5×2
Calculate the product
10
2×210
When a square root of an expression is multiplied by itself,the result is that expression
210
x=±210
Separate the equation into 2 possible cases
x=210x=−210
Solution
x1=−210,x2=210
Show Solution

Solve the equation
Solve for x
Solve for y
x=2−2y+10x=−2−2y+10
Evaluate
y−5=−2(x×1)2
Any expression multiplied by 1 remains the same
y−5=−2x2
Swap the sides of the equation
−2x2=y−5
Change the signs on both sides of the equation
2x2=−y+5
Divide both sides
22x2=2−y+5
Divide the numbers
x2=2−y+5
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±2−y+5
Simplify the expression
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Evaluate
2−y+5
To take a root of a fraction,take the root of the numerator and denominator separately
2−y+5
Multiply by the Conjugate
2×2−y+5×2
Calculate
2−y+5×2
Calculate
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Evaluate
−y+5×2
The product of roots with the same index is equal to the root of the product
(−y+5)×2
Calculate the product
−2y+10
2−2y+10
x=±2−2y+10
Solution
x=2−2y+10x=−2−2y+10
Show Solution

Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
y−5=−2(x1)2
Simplify the expression
y−5=−2x2
To test if the graph of y−5=−2x2 is symmetry with respect to the origin,substitute -x for x and -y for y
−y−5=−2(−x)2
Evaluate
−y−5=−2x2
Solution
Not symmetry with respect to the origin
Show Solution

Identify the conic
Find the standard equation of the parabola
Find the vertex of the parabola
Find the focus of the parabola
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x2=−21(y−5)
Evaluate
y−5=−2(x×1)2
Any expression multiplied by 1 remains the same
y−5=−2x2
Swap the sides of the equation
−2x2=y−5
Multiply both sides of the equation by −21
−2x2(−21)=(y−5)(−21)
Multiply the terms
x2=(y−5)(−21)
Multiply the terms
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Evaluate
(y−5)(−21)
Apply the distributive property
y(−21)−5(−21)
Use the commutative property to reorder the terms
−21y−5(−21)
Multiply the numbers
−21y+25
x2=−21y+25
Solution
x2=−21(y−5)
Show Solution

Rewrite the equation
r=4cos2(θ)−sin(θ)+39cos2(θ)+41r=−4cos2(θ)sin(θ)+39cos2(θ)+41
Evaluate
y−5=−2(x×1)2
Any expression multiplied by 1 remains the same
y−5=−2x2
Move the expression to the left side
y−5+2x2=0
To convert the equation to polar coordinates,substitute x for rcos(θ) and y for rsin(θ)
sin(θ)×r−5+2(cos(θ)×r)2=0
Factor the expression
2cos2(θ)×r2+sin(θ)×r−5=0
Solve using the quadratic formula
r=4cos2(θ)−sin(θ)±sin2(θ)−4×2cos2(θ)(−5)
Simplify
r=4cos2(θ)−sin(θ)±39cos2(θ)+41
Separate the equation into 2 possible cases
r=4cos2(θ)−sin(θ)+39cos2(θ)+41r=4cos2(θ)−sin(θ)−39cos2(θ)+41
Solution
r=4cos2(θ)−sin(θ)+39cos2(θ)+41r=−4cos2(θ)sin(θ)+39cos2(θ)+41
Show Solution

Find the first derivative
Find the derivative with respect to x
Find the derivative with respect to y
dxdy=−4x
Calculate
y−5=−2(x1)2
Simplify the expression
y−5=−2x2
Take the derivative of both sides
dxd(y−5)=dxd(−2x2)
Calculate the derivative
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Evaluate
dxd(y−5)
Use differentiation rules
dxd(y)+dxd(−5)
Evaluate the derivative
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Evaluate
dxd(y)
Use differentiation rules
dyd(y)×dxdy
Use dxdxn=nxn−1 to find derivative
dxdy
dxdy+dxd(−5)
Use dxd(c)=0 to find derivative
dxdy+0
Evaluate
dxdy
dxdy=dxd(−2x2)
Solution
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Evaluate
dxd(−2x2)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
−2×dxd(x2)
Use dxdxn=nxn−1 to find derivative
−2×2x
Multiply the terms
−4x
dxdy=−4x
Show Solution

Find the second derivative
Find the second derivative with respect to x
Find the second derivative with respect to y
dx2d2y=−4
Calculate
y−5=−2(x1)2
Simplify the expression
y−5=−2x2
Take the derivative of both sides
dxd(y−5)=dxd(−2x2)
Calculate the derivative
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Evaluate
dxd(y−5)
Use differentiation rules
dxd(y)+dxd(−5)
Evaluate the derivative
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Evaluate
dxd(y)
Use differentiation rules
dyd(y)×dxdy
Use dxdxn=nxn−1 to find derivative
dxdy
dxdy+dxd(−5)
Use dxd(c)=0 to find derivative
dxdy+0
Evaluate
dxdy
dxdy=dxd(−2x2)
Calculate the derivative
More Steps

Evaluate
dxd(−2x2)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
−2×dxd(x2)
Use dxdxn=nxn−1 to find derivative
−2×2x
Multiply the terms
−4x
dxdy=−4x
Take the derivative of both sides
dxd(dxdy)=dxd(−4x)
Calculate the derivative
dx2d2y=dxd(−4x)
Simplify
dx2d2y=−4×dxd(x)
Rewrite the expression
dx2d2y=−4×1
Solution
dx2d2y=−4
Show Solution
