Question
Function
Find the first partial derivative with respect to y
Find the first partial derivative with respect to x
∂y∂z=2y
Simplify
z=y2−x2
Find the first partial derivative by treating the variable x as a constant and differentiating with respect to y
∂y∂z=∂y∂(y2−x2)
Use differentiation rule ∂x∂(f(x)±g(x))=∂x∂(f(x))±∂x∂(g(x))
∂y∂z=∂y∂(y2)−∂y∂(x2)
Use ∂x∂xn=nxn−1 to find derivative
∂y∂z=2y−∂y∂(x2)
Use ∂x∂(c)=0 to find derivative
∂y∂z=2y−0
Solution
∂y∂z=2y
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Solve the equation
Solve for x
Solve for y
x=−z+y2x=−−z+y2
Evaluate
z=y2−x2
Swap the sides of the equation
y2−x2=z
Move the expression to the right-hand side and change its sign
−x2=z−y2
Change the signs on both sides of the equation
x2=−z+y2
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±−z+y2
Solution
x=−z+y2x=−−z+y2
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