Question Function Find the first partial derivative with respect to x Find the first partial derivative with respect to y ∂x∂z=1 Simplify z=x+yFind the first partial derivative by treating the variable y as a constant and differentiating with respect to x ∂x∂z=∂x∂(x+y)Use differentiation rule ∂x∂(f(x)±g(x))=∂x∂(f(x))±∂x∂(g(x)) ∂x∂z=∂x∂(x)+∂x∂(y)Use ∂x∂xn=nxn−1 to find derivative ∂x∂z=1+∂x∂(y)Use ∂x∂(c)=0 to find derivative ∂x∂z=1+0Solution ∂x∂z=1 Show Solution Solve the equation Solve for x Solve for y x=z−y Evaluate z=x+ySwap the sides of the equation x+y=zSolution x=z−y Show Solution