\left\{ \begin{array} { l } { \frac { x + 1 } { 3 } = \frac { y + 2 } { 4 } } \\ { \frac { x 3 } { 4 } \frac { y 3 } { 3 } = \frac { 1 } { 12 } } \end{array} \right.

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Type your math problem... \left\{ \begin{array} { l } { \frac { x + 1 } { 3 } = \frac { y + 2 } { 4 } } \\ { \frac { x - 3 } { 4 } - \frac { y - 3 } { 3 } = \frac { 1 } { 12 } } \end{array} \right.

Question

{\frac{x + 1}{3} = \frac{y + 2}{4} \frac{x - 3}{4} - \frac{y - 3}{3} = \frac{1}{12}

Solve the system of equations

Solve using the substitution method

Solve using the elimination method

Solve using the Gauss-Jordan method

(x, y) = (2, 2)

Show Solution

\left\{ \begin{array} { l } { \frac { x + 1 } { 3 } = \frac { y + 2 } { 4 } } \\ { \frac { x 3 } { 4 } \frac { y 3 } { 3 } = \frac { 1 } { 12 } } \end{array} \right.

Solve the system of equations

Solve using the substitution method

Solve using the elimination method

Solve using the Gauss-Jordan method

Graph