Question : fracddtheta ( cos(2theta) ) Evaluate the derivative −2sin(2θ) Evaluate dθd(cos(2θ))Use the chain rule dxd(f(g))=dgd(f(g))×dxd(g) where the g=2θ, to find the derivative dgd(cos(g))×dθd(2θ)Use dxd(cosx)=−sinx to find derivative −sin(g)×dθd(2θ)Calculate More Steps Calculate dθd(2θ)Use differentiation rule dxd(cf(x))=c×dxd(f(x)) 2×dθd(θ)Use dxdxn=nxn−1 to find derivative 2×1Any expression multiplied by 1 remains the same 2 −sin(g)×2Substitute back −sin(2θ)×2Solution −2sin(2θ) Show Solution