Question :
x=2-3t , y=5+t
Rewrite the parametric equations
y=317−x
Evaluate
{x=2−3ty=5+t
Choose the parametric equation
x=2−3t
Solve the equation
t=3−x+2
Solution
y=317−x
Show Solution

Find the first derivative
dxdy=−31
Evaluate
{x=2−3ty=5+t
To find the derivative dxdy,first find dtdx and dtdy
dtd(x)=dtd(2−3t)dtd(y)=dtd(5+t)
Find the derivative
More Steps

Evaluate
dtd(x)=dtd(2−3t)
Calculate the derivative
More Steps

Evaluate
dtd(x)
Use differentiation rules
dxd(x)×dtdx
Use dxdxn=nxn−1 to find derivative
dtdx
dtdx=dtd(2−3t)
Calculate the derivative
More Steps

Evaluate
dtd(2−3t)
Use differentiation rule dxd(f(x)±g(x))=dxd(f(x))±dxd(g(x))
dtd(2)−dtd(3t)
Use dxd(c)=0 to find derivative
0−dtd(3t)
Calculate
0−3
Removing 0 doesn't change the value,so remove it from the expression
−3
dtdx=−3
dtdx=−3dtd(y)=dtd(5+t)
Find the derivative
More Steps

Evaluate
dtd(y)=dtd(5+t)
Calculate the derivative
More Steps

Evaluate
dtd(y)
Use differentiation rules
dyd(y)×dtdy
Use dxdxn=nxn−1 to find derivative
dtdy
dtdy=dtd(5+t)
Calculate the derivative
More Steps

Evaluate
dtd(5+t)
Use differentiation rule dxd(f(x)±g(x))=dxd(f(x))±dxd(g(x))
dtd(5)+dtd(t)
Use dxd(c)=0 to find derivative
0+dtd(t)
Use dxdxn=nxn−1 to find derivative
0+1
Removing 0 doesn't change the value,so remove it from the expression
1
dtdy=1
dtdx=−3dtdy=1
Solution
dxdy=−31
Show Solution
