Question :
(1,0) , (0,2)
Find the distance
d=5
Alternative Form
d≈2.236068
Evaluate
(1,0),(0,2)
Let (x1,y1)=(1,0) and (x2,y2)=(0,2)
(x1,y1)=(1,0)(x2,y2)=(0,2)
Use the distance formula d=(x2−x1)2+(y2−y1)2
d=(x2−x1)2+(y2−y1)2
Substitute x1=1,y1=0 and x2=0,y2=2 into the equation
d=(0−1)2+(2−0)2
Removing 0 doesn't change the value,so remove it from the expression
d=(−1)2+(2−0)2
Removing 0 doesn't change the value,so remove it from the expression
d=(−1)2+22
Evaluate the power
d=1+22
Solution
More Steps

Evaluate
1+22
Evaluate the power
1+4
Add the numbers
5
d=5
Alternative Form
d≈2.236068
Show Solution

Midpoint
Find the midpoint between (1,0) and (0,2)
Find the other endpoint if (1,0) is the midpoint
Find the other endpoint if (0,2) is the midpoint
Midpoint=(21,1)
Evaluate
(1,0),(0,2)
Let (x1,y1)=(1,0) and (x2,y2)=(0,2)
(x1,y1)=(1,0)(x2,y2)=(0,2)
Use the midpoint formula Midpoint=(2x1+x2,2y1+y2)
Midpoint=(2x1+x2,2y1+y2)
Substitute x1=1,y1=0 and x2=0,y2=2 into the equation
Midpoint=(21+0,20+2)
Removing 0 doesn't change the value,so remove it from the expression
Midpoint=(21,20+2)
Solution
More Steps

Evaluate
20+2
Removing 0 doesn't change the value,so remove it from the expression
22
Reduce the numbers
11
Calculate
1
Midpoint=(21,1)
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Find the slope of the line
m=−2
Evaluate
(1,0),(0,2)
The slope of the points (x1,y1) and (x2,y2) is m=x2−x1y2−y1
m=0−12−0
Removing 0 doesn't change the value,so remove it from the expression
m=0−12
Removing 0 doesn't change the value,so remove it from the expression
m=−12
Solution
m=−2
Show Solution

Find the equation of the line
Find the equation of the line through (1,0) and (0,2)
Find the equation of the line through (1,0) and (0,2) using the determinant
y=−2x+2
Evaluate
(1,0),(0,2)
The slope of the points (x1,y1) and (x2,y2) is m=x2−x1y2−y1
m=0−12−0
Removing 0 doesn't change the value,so remove it from the expression
m=0−12
Removing 0 doesn't change the value,so remove it from the expression
m=−12
Divide the terms
m=−2
To apply the point-slope formula y−y1=m(x−x1),use the slope m=−2 and point (1,0) as (x1,y1)
y−0=−2(x−1)
Removing 0 doesn't change the value,so remove it from the expression
y=−2(x−1)
Solution
More Steps

Evaluate
−2(x−1)
Apply the distributive property
−2x−(−2×1)
Any expression multiplied by 1 remains the same
−2x−(−2)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−2x+2
y=−2x+2
Show Solution
