fractan^{2alpha + 1}sec{alpha} = secalpha

Frequently Asked Questions

• $$\text{Resolver para }\alpha$$ \(\frac{\tan^{2}{\alpha} + 1}{\sec{\alpha}} = \sec{\alpha}\)

  

  $$\alpha \ne \frac{\pi }{2}+k\pi ,k\in \mathbb{Z}$$

• Verificar \(\frac{\tan^{2}{\alpha} + 1}{\sec{\alpha}} = \sec{\alpha}\)

  

  $$\text{true}$$