Question
Evaluate the integral
Evaluate using formulas and rules
8π2−4π+8
Alternative Form
≈0.662904
Evaluate
∫02π∫0xxsin(y)dydx
To evaluate the iterated inter,first evaluate the inner integral
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Evaluate
∫0xxsin(y)dy
Evaluate the integral
∫xsin(y)dy
Use the property of integral ∫kf(x)dx=k∫f(x)dx
x×∫sin(y)dy
Use the property of integral ∫sin(x)dx=−cos(x)
x(−cos(y))
Rewrite the expression
−xcos(y)
Return the limits
(−xcos(y))0x
Calculate the value
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Substitute the values into formula
−xcos(x)−(−xcos(0))
Calculate
−xcos(x)−(−x×1)
Any expression multiplied by 1 remains the same
−xcos(x)−(−x)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−xcos(x)+x
−xcos(x)+x
∫02π(−xcos(x)+x)dx
Evaluate the integral
∫(−xcos(x)+x)dx
Use the property of integral ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx
∫−xcos(x)dx+∫xdx
Evaluate the integral
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Evaluate
∫−xcos(x)dx
Use the property of integral ∫kf(x)dx=k∫f(x)dx
−∫xcos(x)dx
Prepare for integration by parts
u=xdv=cos(x)dx
Calculate the derivative
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Calculate the derivative
u=x
Evaluate the derivative
du=x′dx
Evaluate the derivative
du=1dx
Simplify the expression
du=dx
du=dxdv=cos(x)dx
Evaluate the integral
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Evaluate the integral
dv=cos(x)dx
Evaluate the integral
∫1dv=∫cos(x)dx
Evaluate the integral
v=sin(x)
du=dxv=sin(x)
Substitute u=x、v=sin(x)、du=dx、dv=cos(x)dx for ∫udv=uv−∫vdu
−(xsin(x)−∫1×sin(x)dx)
Calculate
−(xsin(x)−∫sin(x)dx)
Calculate
−xsin(x)+∫sin(x)dx
Use the property of integral ∫sin(x)dx=−cos(x)
−xsin(x)−cos(x)
−xsin(x)−cos(x)+∫xdx
Evaluate the integral
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Evaluate
∫xdx
Use the property of integral ∫xndx=n+1xn+1
1+1x1+1
Add the numbers
1+1x2
Add the numbers
2x2
−xsin(x)−cos(x)+2x2
Return the limits
(−xsin(x)−cos(x)+2x2)02π
Solution
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Substitute the values into formula
−2πsin(2π)−cos(2π)+2(2π)2−(−0×sin(0)−cos(0)+202)
Any expression multiplied by 0 equals 0
−2πsin(2π)−cos(2π)+2(2π)2−(0−cos(0)+202)
Calculate
−2πsin(2π)−cos(2π)+2(2π)2−(0−cos(0)+20)
Calculate
−2π×1−cos(2π)+2(2π)2−(0−cos(0)+20)
Calculate
−2π×1−cos(2π)+2(2π)2−(0−1+20)
Divide the terms
−2π×1−cos(2π)+2(2π)2−(0−1+0)
Calculate
−2π×1−0+2(2π)2−(0−1+0)
Simplify
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Evaluate
2(2π)2
Simplify the expression
222π2
Rewrite the expression
23π2
−2π×1−0+23π2−(0−1+0)
Any expression multiplied by 1 remains the same
−2π−0+23π2−(0−1+0)
Removing 0 doesn't change the value,so remove it from the expression
−2π−0+23π2−(−1)
Removing 0 doesn't change the value,so remove it from the expression
−2π+23π2−(−1)
Evaluate the power
−2π+8π2−(−1)
Add the numbers
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Evaluate
−2π+8π2
Write all numerators above the least common denominator 8
−2×4π×4+8π2
Calculate
−84π+8π2
Add the terms
8−4π+π2
Rewrite the fraction
8π2−4π
8π2−4π−(−1)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
8π2−4π+1
Write all numerators above the least common denominator 8
8π2−4π+1×81×8
Calculate
8π2−4π+88
Add the terms
8π2−4π+8
8π2−4π+8
Alternative Form
≈0.662904
Show Solution