\left(\frac{\left(\frac{k}{k^{1/6}}\right)}{k} \cdot \frac{1}{k^{ 2/13}} \cdot \frac{\left(\frac{k}{\left(\frac{k}{\left(\frac{k}{\left(\frac{k^{ 1/2}}{k} \cdot k\right)}\right)}\right) \cdot k \cdot k \cdot k}{k}\right)}{k} \cdot k \cdot k^{ 1/8})