Solve (2 l + 1) n_l < 2m \mu \alpha

Evaluate

(2 l + 1) n_{l} < 2 m μα

Multiply the terms

n_{l} (2 l + 1) < 2 m μα

Divide both sides

\frac{n _{l} ( 2 l + 1 )}{n _{l}} < \frac{2 m μα}{n _{l}}

Divide the numbers

2 l + 1 < \frac{2 m μα}{n _{l}}

Move the constant to the right side

2 l < \frac{2 m μα}{n _{l}} - 1

Subtract the terms

More Steps

2 l < \frac{2 m μα - n _{l}}{n _{l}}

Multiply by the reciprocal

2 l \times \frac{1}{2} < \frac{2 m μα - n _{l}}{n _{l}} \times \frac{1}{2}

Multiply

l < \frac{2 m μα - n _{l}}{n _{l}} \times \frac{1}{2}

Solution

More Steps

l < \frac{2 m μα - n _{l}}{2 n _{l}}

(2 l + 1) n_l < 2m \mu \alpha