(3^(1 9r))

Type your math problem... (243^(3n-2)) / (27 * 3^(2-1r)) = (81 * 9^(2n-3)) / (3^(1-9r))

Question

\frac{24 3 ^{3 n - 2}}{27 \times 3 ^{2 - 1 \times r}} = \frac{81 \times 9 ^{2 n - 3}}{3 ^{1 - 9 r}}

Solve the equation

n = \frac{12 + 8 r}{11}

Show Solution