Solve (a-8/a+8-a+8/a-8) 16a/64-a^2

Question

Simplify the expression

- a^{2}

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a = 0

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a \in \emptyset

Evaluate

(a - \frac{8}{a} + 8 - a + \frac{8}{a} - 8) (16 \times \frac{a}{64}) - a^{2}

To find the roots of the expression,set the expression equal to 0

(a - \frac{8}{a} + 8 - a + \frac{8}{a} - 8) (16 \times \frac{a}{64}) - a^{2} = 0

Find the domain

(a - \frac{8}{a} + 8 - a + \frac{8}{a} - 8) (16 \times \frac{a}{64}) - a^{2} = 0, a \neq = 0

Calculate

(a - \frac{8}{a} + 8 - a + \frac{8}{a} - 8) (16 \times \frac{a}{64}) - a^{2} = 0

Subtract the terms

More Steps

(\frac{a ^{2} - 8}{a} + 8 - a + \frac{8}{a} - 8) (16 \times \frac{a}{64}) - a^{2} = 0

Add the terms

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(\frac{a ^{2} - 8 + 8 a}{a} - a + \frac{8}{a} - 8) (16 \times \frac{a}{64}) - a^{2} = 0

Subtract the terms

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(\frac{- 8 + 8 a}{a} + \frac{8}{a} - 8) (16 \times \frac{a}{64}) - a^{2} = 0

Add the terms

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(8 - 8) (16 \times \frac{a}{64}) - a^{2} = 0

Subtract the terms

0 \times (16 \times \frac{a}{64}) - a^{2} = 0

Multiply the terms

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0 \times \frac{a}{4} - a^{2} = 0

Any expression multiplied by 0 equals 0

0 - a^{2} = 0

Removing 0 doesn't change the value,so remove it from the expression

- a^{2} = 0

Change the signs on both sides of the equation

a^{2} = 0

The only way a power can be 0 is when the base equals 0

a = 0

Check if the solution is in the defined range

a = 0, a \neq = 0

Solution

a \in \emptyset

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