Question
Simplify the expression
Solution
x3−8x2+13x−6
Evaluate
(x−1)(x−1)(x−6)
Multiply the first two terms
(x−1)2(x−6)
Expand the expression
More Steps

Evaluate
(x−1)2
Use (a−b)2=a2−2ab+b2 to expand the expression
x2−2x×1+12
Calculate
x2−2x+1
(x2−2x+1)(x−6)
Apply the distributive property
x2×x−x2×6−2x×x−(−2x×6)+1×x−1×6
Multiply the terms
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Evaluate
x2×x
Use the product rule an×am=an+m to simplify the expression
x2+1
Add the numbers
x3
x3−x2×6−2x×x−(−2x×6)+1×x−1×6
Use the commutative property to reorder the terms
x3−6x2−2x×x−(−2x×6)+1×x−1×6
Multiply the terms
x3−6x2−2x2−(−2x×6)+1×x−1×6
Multiply the numbers
x3−6x2−2x2−(−12x)+1×x−1×6
Any expression multiplied by 1 remains the same
x3−6x2−2x2−(−12x)+x−1×6
Any expression multiplied by 1 remains the same
x3−6x2−2x2−(−12x)+x−6
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
x3−6x2−2x2+12x+x−6
Subtract the terms
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Evaluate
−6x2−2x2
Collect like terms by calculating the sum or difference of their coefficients
(−6−2)x2
Subtract the numbers
−8x2
x3−8x2+12x+x−6
Solution
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Evaluate
12x+x
Collect like terms by calculating the sum or difference of their coefficients
(12+1)x
Add the numbers
13x
x3−8x2+13x−6
Show Solution
Find the roots
Find the roots of the algebra expression
x1=1,x2=6
Evaluate
(x−1)(x−1)(x−6)
To find the roots of the expression,set the expression equal to 0
(x−1)(x−1)(x−6)=0
Multiply the first two terms
(x−1)2(x−6)=0
Separate the equation into 2 possible cases
(x−1)2=0x−6=0
Solve the equation
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Evaluate
(x−1)2=0
The only way a power can be 0 is when the base equals 0
x−1=0
Move the constant to the right-hand side and change its sign
x=0+1
Removing 0 doesn't change the value,so remove it from the expression
x=1
x=1x−6=0
Solve the equation
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Evaluate
x−6=0
Move the constant to the right-hand side and change its sign
x=0+6
Removing 0 doesn't change the value,so remove it from the expression
x=6
x=1x=6
Solution
x1=1,x2=6
Show Solution