Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
Solve for x
x∈(−∞,−27)∪(0,+∞)
Evaluate
−2x2−7x<0
Rewrite the expression
−2x2−7x=0
Factor the expression
More Steps

Evaluate
−2x2−7x
Rewrite the expression
−x×2x−x×7
Factor out −x from the expression
−x(2x+7)
−x(2x+7)=0
When the product of factors equals 0,at least one factor is 0
−x=02x+7=0
Solve the equation for x
x=02x+7=0
Solve the equation for x
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Evaluate
2x+7=0
Move the constant to the right-hand side and change its sign
2x=0−7
Removing 0 doesn't change the value,so remove it from the expression
2x=−7
Divide both sides
22x=2−7
Divide the numbers
x=2−7
Use b−a=−ba=−ba to rewrite the fraction
x=−27
x=0x=−27
Determine the test intervals using the critical values
x<−27−27<x<0x>0
Choose a value form each interval
x1=−5x2=−2x3=1
To determine if x<−27 is the solution to the inequality,test if the chosen value x=−5 satisfies the initial inequality
More Steps

Evaluate
−2(−5)2−7(−5)<0
Simplify
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Evaluate
−2(−5)2−7(−5)
Multiply the terms
−50−7(−5)
Multiply the numbers
−50−(−35)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−50+35
Add the numbers
−15
−15<0
Check the inequality
true
x<−27 is the solutionx2=−2x3=1
To determine if −27<x<0 is the solution to the inequality,test if the chosen value x=−2 satisfies the initial inequality
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Evaluate
−2(−2)2−7(−2)<0
Simplify
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Evaluate
−2(−2)2−7(−2)
Multiply the terms
−23−7(−2)
Multiply the numbers
−23−(−14)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−23+14
Evaluate the power
−8+14
Add the numbers
6
6<0
Check the inequality
false
x<−27 is the solution−27<x<0 is not a solutionx3=1
To determine if x>0 is the solution to the inequality,test if the chosen value x=1 satisfies the initial inequality
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Evaluate
−2×12−7×1<0
Simplify
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Evaluate
−2×12−7×1
1 raised to any power equals to 1
−2×1−7×1
Any expression multiplied by 1 remains the same
−2−7×1
Any expression multiplied by 1 remains the same
−2−7
Subtract the numbers
−9
−9<0
Check the inequality
true
x<−27 is the solution−27<x<0 is not a solutionx>0 is the solution
Solution
x∈(−∞,−27)∪(0,+∞)
Show Solution
