Question
Find the roots
Find the roots of the algebra expression
x1=−1314+210,x2=13−14+210
Alternative Form
x1≈−1.563427,x2≈−0.590419
Evaluate
13x2+28x+12
To find the roots of the expression,set the expression equal to 0
13x2+28x+12=0
Substitute a=13,b=28 and c=12 into the quadratic formula x=2a−b±b2−4ac
x=2×13−28±282−4×13×12
Simplify the expression
x=26−28±282−4×13×12
Simplify the expression
More Steps

Evaluate
282−4×13×12
Multiply the terms
More Steps

Multiply the terms
4×13×12
Multiply the terms
52×12
Multiply the numbers
624
282−624
Evaluate the power
784−624
Subtract the numbers
160
x=26−28±160
Simplify the radical expression
More Steps

Evaluate
160
Write the expression as a product where the root of one of the factors can be evaluated
16×10
Write the number in exponential form with the base of 4
42×10
The root of a product is equal to the product of the roots of each factor
42×10
Reduce the index of the radical and exponent with 2
410
x=26−28±410
Separate the equation into 2 possible cases
x=26−28+410x=26−28−410
Simplify the expression
More Steps

Evaluate
x=26−28+410
Divide the terms
More Steps

Evaluate
26−28+410
Rewrite the expression
262(−14+210)
Cancel out the common factor 2
13−14+210
x=13−14+210
x=13−14+210x=26−28−410
Simplify the expression
More Steps

Evaluate
x=26−28−410
Divide the terms
More Steps

Evaluate
26−28−410
Rewrite the expression
262(−14−210)
Cancel out the common factor 2
13−14−210
Use b−a=−ba=−ba to rewrite the fraction
−1314+210
x=−1314+210
x=13−14+210x=−1314+210
Solution
x1=−1314+210,x2=13−14+210
Alternative Form
x1≈−1.563427,x2≈−0.590419
Show Solution