Question
Solve the equation
Solve for b
b=−1
Evaluate
2(2b+3)+3b=−1
Move the expression to the left side
2(2b+3)+3b−(−1)=0
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
2(2b+3)+3b+1=0
Calculate
More Steps

Evaluate
2(2b+3)+3b+1
Expand the expression
More Steps

Calculate
2(2b+3)
Apply the distributive property
2×2b+2×3
Multiply the numbers
4b+2×3
Multiply the numbers
4b+6
4b+6+3b+1
Add the terms
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Evaluate
4b+3b
Collect like terms by calculating the sum or difference of their coefficients
(4+3)b
Add the numbers
7b
7b+6+1
Add the numbers
7b+7
7b+7=0
Move the constant to the right-hand side and change its sign
7b=0−7
Removing 0 doesn't change the value,so remove it from the expression
7b=−7
Divide both sides
77b=7−7
Divide the numbers
b=7−7
Solution
More Steps

Evaluate
7−7
Reduce the numbers
1−1
Calculate
−1
b=−1
Show Solution