Solve 2x^(2)-20x-13=0

Evaluate

2 x^{2} - 20 x - 13 = 0

Substitute a= 2,b= - 20 and c= - 13 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{20 \pm ( - 20 ) ^{2} - 4 \times 2 ( - 13 )}{2 \times 2}

Simplify the expression

x = \frac{20 \pm ( - 20 ) ^{2} - 4 \times 2 ( - 13 )}{4}

Simplify the expression

More Steps

x = \frac{20 \pm 504}{4}

Simplify the radical expression

More Steps

x = \frac{20 \pm 6 14}{4}

Separate the equation into 2 possible cases

x = \frac{20 + 6 14}{4} x = \frac{20 - 6 14}{4}

Simplify the expression

More Steps

x = \frac{10 + 3 14}{2} x = \frac{20 - 6 14}{4}

Simplify the expression

More Steps

x = \frac{10 + 3 14}{2} x = \frac{10 - 3 14}{2}

Solution

x_{1} = \frac{10 - 3 14}{2}, x_{2} = \frac{10 + 3 14}{2}

Alternative Form

x_{1} \approx - 0.612486, x_{2} \approx 10.612486

2x^(2) 20x 13=0