Solve 2x^2-32x+12

Evaluate

2 x^{2} - 32 x + 12

To find the roots of the expression,set the expression equal to 0

2 x^{2} - 32 x + 12 = 0

Substitute a= 2,b= - 32 and c= 12 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{32 \pm ( - 32 ) ^{2} - 4 \times 2 \times 12}{2 \times 2}

Simplify the expression

x = \frac{32 \pm ( - 32 ) ^{2} - 4 \times 2 \times 12}{4}

Simplify the expression

More Steps

x = \frac{32 \pm 928}{4}

Simplify the radical expression

More Steps

x = \frac{32 \pm 4 58}{4}

Separate the equation into 2 possible cases

x = \frac{32 + 4 58}{4} x = \frac{32 - 4 58}{4}

Simplify the expression

More Steps

x = 8 + 58 x = \frac{32 - 4 58}{4}

Simplify the expression

More Steps

x = 8 + 58 x = 8 - 58

Solution

x_{1} = 8 - 58, x_{2} = 8 + 58

Alternative Form

x_{1} \approx 0.384227, x_{2} \approx 15.615773

2x^2 32x+12