Solve 2x^3 -x^2 -20x+10

Question

Factor the expression

Factor

(2 x - 1) (x^{2} - 10)

Evaluate

2 x^{3} - x^{2} - 20 x + 10

Calculate

2 x^{3} - 20 x - x^{2} + 10

Rewrite the expression

2 x \times x^{2} - 2 x \times 10 - x^{2} + 10

Factor out 2 x from the expression

2 x (x^{2} - 10) - x^{2} + 10

Factor out - 1 from the expression

2 x (x^{2} - 10) - (x^{2} - 10)

Solution

(2 x - 1) (x^{2} - 10)

Show Solution

Find the roots of the algebra expression

x_{1} = - 10, x_{2} = \frac{1}{2}, x_{3} = 10

Alternative Form

x_{1} \approx - 3.162278, x_{2} = 0.5, x_{3} \approx 3.162278

Evaluate

2 x^{3} - x^{2} - 20 x + 10

To find the roots of the expression,set the expression equal to 0

2 x^{3} - x^{2} - 20 x + 10 = 0

Factor the expression

(2 x - 1) (x^{2} - 10) = 0

Separate the equation into 2 possible cases

2 x - 1 = 0 x^{2} - 10 = 0

Solve the equation

More Steps

Evaluate

2 x - 1 = 0

Move the constant to the right-hand side and change its sign

2 x = 0 + 1

Removing 0 doesn't change the value,so remove it from the expression

2 x = 1

Divide both sides

\frac{2 x}{2} = \frac{1}{2}

Divide the numbers

x = \frac{1}{2}

x = \frac{1}{2} x^{2} - 10 = 0

Solve the equation

More Steps

Evaluate

x^{2} - 10 = 0

Move the constant to the right-hand side and change its sign

x^{2} = 0 + 10

Removing 0 doesn't change the value,so remove it from the expression

x^{2} = 10

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm 10

Separate the equation into 2 possible cases

x = 10 x = - 10

x = \frac{1}{2} x = 10 x = - 10

Solution

x_{1} = - 10, x_{2} = \frac{1}{2}, x_{3} = 10

Alternative Form

x_{1} \approx - 3.162278, x_{2} = 0.5, x_{3} \approx 3.162278

Show Solution