Question
Factor the expression
Factor
(2x−7)(3x+5)
Evaluate
6x2−11x−35
Rewrite the expression
6x2+(10−21)x−35
Calculate
6x2+10x−21x−35
Rewrite the expression
2x×3x+2x×5−7×3x−7×5
Factor out 2x from the expression
2x(3x+5)−7×3x−7×5
Factor out −7 from the expression
2x(3x+5)−7(3x+5)
Solution
(2x−7)(3x+5)
Show Solution

Find the roots
Find the roots of the algebra expression
x1=−35,x2=27
Alternative Form
x1=−1.6˙,x2=3.5
Evaluate
6x2−11x−35
To find the roots of the expression,set the expression equal to 0
6x2−11x−35=0
Factor the expression
More Steps

Evaluate
6x2−11x−35
Rewrite the expression
6x2+(10−21)x−35
Calculate
6x2+10x−21x−35
Rewrite the expression
2x×3x+2x×5−7×3x−7×5
Factor out 2x from the expression
2x(3x+5)−7×3x−7×5
Factor out −7 from the expression
2x(3x+5)−7(3x+5)
Factor out 3x+5 from the expression
(2x−7)(3x+5)
(2x−7)(3x+5)=0
When the product of factors equals 0,at least one factor is 0
2x−7=03x+5=0
Solve the equation for x
More Steps

Evaluate
2x−7=0
Move the constant to the right-hand side and change its sign
2x=0+7
Removing 0 doesn't change the value,so remove it from the expression
2x=7
Divide both sides
22x=27
Divide the numbers
x=27
x=273x+5=0
Solve the equation for x
More Steps

Evaluate
3x+5=0
Move the constant to the right-hand side and change its sign
3x=0−5
Removing 0 doesn't change the value,so remove it from the expression
3x=−5
Divide both sides
33x=3−5
Divide the numbers
x=3−5
Use b−a=−ba=−ba to rewrite the fraction
x=−35
x=27x=−35
Solution
x1=−35,x2=27
Alternative Form
x1=−1.6˙,x2=3.5
Show Solution
