Question
Solve the equation
(c1,d1,p1)=(c,0,p),(c,p)∈R2(c2,d2,p2)=(c,d,0),(c,d)∈R2(c3,d3,p3)=(0,d,p),(d,p)∈R2
Evaluate
dpic=dp(i−1)c
Use the commutative property to reorder the terms
idpc=dp(i−1)c
Simplify
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Evaluate
dp(i−1)c
Multiply the terms
dpc(i−1)
Multiply the first two terms
(i−1)dpc
Calculate
(−1+i)dpc
idpc=(−1+i)dpc
Move the expression to the left side
idpc−(−1+i)dpc=0
Subtract the terms
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Evaluate
idpc−(−1+i)dpc
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
idpc+(1−i)dpc
Collect like terms by calculating the sum or difference of their coefficients
(i+1−i)dpc
Add the numbers
dpc
dpc=0
Separate the equation into 3 possible cases
d=0p=0c=0
Find the union
c=0d=0p=0
Solution
(c1,d1,p1)=(c,0,p),(c,p)∈R2(c2,d2,p2)=(c,d,0),(c,d)∈R2(c3,d3,p3)=(0,d,p),(d,p)∈R2
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