Solve p+o^2=p^4o10

Evaluate

p + o^{2} = p^{4} o \times 10

Use the commutative property to reorder the terms

p + o^{2} = 10 p^{4} o

Move the expression to the left side

p + o^{2} - 10 p^{4} o = 0

Rewrite in standard form

o^{2} - 10 p^{4} o + p = 0

Substitute a= 1,b= - 10 p^{4} and c= p into the quadratic formula o = \frac{- b \pm b ^{2} - 4 a c}{2 a}

o = \frac{10 p ^{4} \pm ( - 10 p ^{4} ) ^{2} - 4 p}{2}

Simplify the expression

o = \frac{10 p ^{4} \pm 100 p ^{8} - 4 p}{2}

Simplify the radical expression

More Steps

o = \frac{10 p ^{4} \pm 2 25 p ^{8} - p}{2}

Separate the equation into 2 possible cases

o = \frac{10 p ^{4} + 2 25 p ^{8} - p}{2} o = \frac{10 p ^{4} - 2 25 p ^{8} - p}{2}

Simplify the expression

More Steps

o = 5 p^{4} + 25 p^{8} - p o = \frac{10 p ^{4} - 2 25 p ^{8} - p}{2}

Solution

More Steps

o = 5 p^{4} + 25 p^{8} - p o = 5 p^{4} - 25 p^{8} - p

P+o^2=p^4o10