Question
Solve the differential equation
u=Cv,C∈R
Evaluate
u=(u)′×v
Simplify
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Evaluate
(u)′×v
Use dxdxn=nxn−1 to find derivative
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Evaluate
(u)′
Rewrite the expression
dud(u)
Use dxdxn=nxn−1 to find derivative
1
1×v
Any expression multiplied by 1 remains the same
v
u=v
Remove the parentheses
u=u′v
Use the commutative property to reorder the terms
u=vu′
Rewrite the expression
vu′=u
Rewrite the expression
vdvdu=u
Rewrite the expression
u1×vdvdu=u×u1
Multiply the terms
u1×vdvdu=1
Rewrite the expression
u1×dvdu=v1
Transform the expression
u1×du=v1×dv
Integrate the left-hand side of the equation with respect to u and the right-hand side of the equation with respect to v
∫u1du=∫v1dv
Calculate
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Evaluate
∫u1du
Use the property of integral ∫x1dx=ln∣x∣
ln(u)
Add the constant of integral C1
ln(u)+C1,C1∈R
ln(u)+C1=∫v1dv,C1∈R
Calculate
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Evaluate
∫v1dv
Use the property of integral ∫x1dx=ln∣x∣
ln(v)
Add the constant of integral C2
ln(v)+C2,C2∈R
ln(u)+C1=ln(v)+C2,C1∈R,C2∈R
Since the integral constants C1 and C2 are arbitrary constants, replace them with constant C
ln(u)=ln(v)+C,C∈R
Calculate
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Evaluate
ln(u)=ln(v)+C
Convert the logarithm into exponential form using the fact that logax=b is equal to x=ab
u=eln(v)+C
Evaluate the power
u=eCv
u=eCv,C∈R
Solution
u=Cv,C∈R
Show Solution
