Question
Solve the system of equations
Solve using the substitution method
Solve using the elimination method
(x,y)=(0,−55+5)
Alternative Form
(x,y)≈(0,−1.447214)
Evaluate
{xy=0(21−5)(21×5)y=1
Calculate
More Steps
Evaluate
(21−5)(21×5)y
Remove the unnecessary parentheses
21−5×(21×5)y
Any expression multiplied by 1 remains the same
21−5×(25)y
Remove the unnecessary parentheses
21−5×25y
Multiply the terms
More Steps
Evaluate
21−5×25
To multiply the fractions,multiply the numerators and denominators separately
2×2(1−5)5
Multiply the numbers
2×25−5
Multiply the numbers
45−5
45−5×y
{xy=045−5×y=1
Solve the equation for y
More Steps
Evaluate
45−5×y=1
Rewrite the expression
4(5−5)y=1
Cross multiply
(5−5)y=4
Divide both sides
5−5(5−5)y=5−54
Divide the numbers
y=5−54
Rearrange the numbers
More Steps
Evaluate
5−54
Multiply by the Conjugate
(5−5)(5+5)4(5+5)
Multiply the numbers
−204(5+5)
Factor the expression
−5×44(5+5)
Reduce the fraction
−55+5
Calculate
−55+5
y=−55+5
{xy=0y=−55+5
Substitute the given value of y into the equation xy=0
x(−55+5)=0
Use the commutative property to reorder the terms
−55+5×x=0
Simplify
(−5−5)x=0
Change the signs on both sides of the equation
(5+5)x=0
Rewrite the expression
x=0
Calculate
{x=0y=−55+5
Check the solution
More Steps
Check the solution
⎩⎨⎧0×(−55+5)=0(21−5)(21×5)(−55+5)=1
Simplify
{0=01=1
Evaluate
true
{x=0y=−55+5
Solution
(x,y)=(0,−55+5)
Alternative Form
(x,y)≈(0,−1.447214)
Show Solution