Question
Function
Find the vertex
Find the axis of symmetry
Rewrite in vertex form
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(54,−536)
Evaluate
y=5x2−8x−4
Find the x-coordinate of the vertex by substituting a=5 and b=−8 into x = −2ab
x=−2×5−8
Solve the equation for x
x=54
Find the y-coordinate of the vertex by evaluating the function for x=54
y=5(54)2−8×54−4
Calculate
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Evaluate
5(54)2−8×54−4
Multiply the terms
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Evaluate
5(54)2
Evaluate the power
5×2516
Multiply the numbers
516
516−8×54−4
Multiply the numbers
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Evaluate
−8×54
Multiply the numbers
−58×4
Multiply the numbers
−532
516−532−4
Reduce fractions to a common denominator
516−532−54×5
Write all numerators above the common denominator
516−32−4×5
Multiply the numbers
516−32−20
Subtract the numbers
5−36
Use b−a=−ba=−ba to rewrite the fraction
−536
y=−536
Solution
(54,−536)
Show Solution
Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
y=5x2−8x−4
To test if the graph of y=5x2−8x−4 is symmetry with respect to the origin,substitute -x for x and -y for y
−y=5(−x)2−8(−x)−4
Simplify
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Evaluate
5(−x)2−8(−x)−4
Multiply the terms
5x2−8(−x)−4
Multiply the numbers
5x2+8x−4
−y=5x2+8x−4
Change the signs both sides
y=−5x2−8x+4
Solution
Not symmetry with respect to the origin
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Identify the conic
Find the standard equation of the parabola
Find the vertex of the parabola
Find the focus of the parabola
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(x−54)2=51(y+536)
Evaluate
y=5x2−8x−4
Swap the sides of the equation
5x2−8x−4=y
Move the constant to the right-hand side and change its sign
5x2−8x=y−(−4)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
5x2−8x=y+4
Multiply both sides of the equation by 51
(5x2−8x)×51=(y+4)×51
Multiply the terms
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Evaluate
(5x2−8x)×51
Use the the distributive property to expand the expression
5x2×51−8x×51
Multiply the numbers
x2−8x×51
Multiply the numbers
x2−58x
x2−58x=(y+4)×51
Multiply the terms
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Evaluate
(y+4)×51
Apply the distributive property
y×51+4×51
Use the commutative property to reorder the terms
51y+4×51
Multiply the numbers
51y+54
x2−58x=51y+54
To complete the square, the same value needs to be added to both sides
x2−58x+2516=51y+54+2516
Use a2−2ab+b2=(a−b)2 to factor the expression
(x−54)2=51y+54+2516
Add the numbers
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Evaluate
54+2516
Reduce fractions to a common denominator
5×54×5+2516
Multiply the numbers
254×5+2516
Write all numerators above the common denominator
254×5+16
Multiply the numbers
2520+16
Add the numbers
2536
(x−54)2=51y+2536
Solution
(x−54)2=51(y+536)
Show Solution
Solve the equation
Solve for x
x=536+5y+4x=5−36+5y+4
Evaluate
y=5x2−8x−4
Swap the sides of the equation
5x2−8x−4=y
Move the expression to the left side
5x2−8x−4−y=0
Move the constant to the right side
5x2−8x=0−(−4−y)
Add the terms
5x2−8x=4+y
Evaluate
x2−58x=54+y
Add the same value to both sides
x2−58x+2516=54+y+2516
Evaluate
x2−58x+2516=2536+5y
Evaluate
(x−54)2=2536+5y
Take the root of both sides of the equation and remember to use both positive and negative roots
x−54=±2536+5y
Simplify the expression
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Evaluate
2536+5y
To take a root of a fraction,take the root of the numerator and denominator separately
2536+5y
Simplify the radical expression
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Evaluate
25
Write the number in exponential form with the base of 5
52
Reduce the index of the radical and exponent with 2
5
536+5y
x−54=±536+5y
Separate the equation into 2 possible cases
x−54=536+5yx−54=−536+5y
Calculate
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Evaluate
x−54=536+5y
Move the constant to the right-hand side and change its sign
x=536+5y+54
Write all numerators above the common denominator
x=536+5y+4
x=536+5y+4x−54=−536+5y
Solution
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Evaluate
x−54=−536+5y
Move the constant to the right-hand side and change its sign
x=−536+5y+54
Write all numerators above the common denominator
x=5−36+5y+4
x=536+5y+4x=5−36+5y+4
Show Solution
Rewrite the equation
Rewrite in polar form
r=10cos2(θ)sin(θ)+8cos(θ)−1+143cos2(θ)+8sin(2θ)r=10cos2(θ)sin(θ)+8cos(θ)+1+143cos2(θ)+8sin(2θ)
Evaluate
y=5x2−8x−4
Move the expression to the left side
y−5x2+8x=−4
To convert the equation to polar coordinates,substitute rcos(θ) for x and rsin(θ) for y
sin(θ)×r−5(cos(θ)×r)2+8cos(θ)×r=−4
Factor the expression
−5cos2(θ)×r2+(sin(θ)+8cos(θ))r=−4
Subtract the terms
−5cos2(θ)×r2+(sin(θ)+8cos(θ))r−(−4)=−4−(−4)
Evaluate
−5cos2(θ)×r2+(sin(θ)+8cos(θ))r+4=0
Solve using the quadratic formula
r=−10cos2(θ)−sin(θ)−8cos(θ)±(sin(θ)+8cos(θ))2−4(−5cos2(θ))×4
Simplify
r=−10cos2(θ)−sin(θ)−8cos(θ)±1+143cos2(θ)+8sin(2θ)
Separate the equation into 2 possible cases
r=−10cos2(θ)−sin(θ)−8cos(θ)+1+143cos2(θ)+8sin(2θ)r=−10cos2(θ)−sin(θ)−8cos(θ)−1+143cos2(θ)+8sin(2θ)
Use b−a=−ba=−ba to rewrite the fraction
r=10cos2(θ)sin(θ)+8cos(θ)−1+143cos2(θ)+8sin(2θ)r=−10cos2(θ)−sin(θ)−8cos(θ)−1+143cos2(θ)+8sin(2θ)
Solution
r=10cos2(θ)sin(θ)+8cos(θ)−1+143cos2(θ)+8sin(2θ)r=10cos2(θ)sin(θ)+8cos(θ)+1+143cos2(θ)+8sin(2θ)
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