Question
Function
Evaluate the derivative
Find the domain
Find the x-intercept/zero
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y′=x2x2+6
Evaluate
y=xx2+x−6−2
Take the derivative of both sides
y′=dxd(xx2+x−6−2)
Use differentiation rule dxd(f(x)±g(x))=dxd(f(x))±dxd(g(x))
y′=dxd(xx2+x−6)−dxd(2)
Calculate
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Calculate
dxd(xx2+x−6)
Use differentiation rule dxd(g(x)f(x))=(g(x))2dxd(f(x))×g(x)−f(x)×dxd(g(x))
x2dxd(x2+x−6)×x−(x2+x−6)×dxd(x)
Calculate
x2(2x+1)x−(x2+x−6)×dxd(x)
Use dxdxn=nxn−1 to find derivative
x2(2x+1)x−(x2+x−6)×1
Multiply the terms
x2x(2x+1)−(x2+x−6)×1
Any expression multiplied by 1 remains the same
x2x(2x+1)−(x2+x−6)
Subtract the terms
x2x2+6
y′=x2x2+6−dxd(2)
Use dxd(c)=0 to find derivative
y′=x2x2+6−0
Solution
y′=x2x2+6
Show Solution
Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
y=xx2+x−6−2
To test if the graph of y=xx2+x−6−2 is symmetry with respect to the origin,substitute -x for x and -y for y
−y=−x(−x)2−x−6−2
Simplify
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Evaluate
−x(−x)2−x−6−2
Rewrite the expression
−xx2−x−6−2
Use b−a=−ba=−ba to rewrite the fraction
−xx2−x−6−2
−y=−xx2−x−6−2
Change the signs both sides
y=xx2−x−6+2
Solution
Not symmetry with respect to the origin
Show Solution
Solve the equation
Solve for x
Solve for y
x=225+2y+y2+1+yx=2−25+2y+y2+1+y
Evaluate
y=xx2+x−6−2
Swap the sides of the equation
xx2+x−6−2=y
Move the constant to the right-hand side and change its sign
xx2+x−6=y+2
Multiply both sides of the equation by LCD
xx2+x−6×x=(y+2)x
Simplify the equation
x2+x−6=(y+2)x
Move the expression to the left side
x2+x−6−(y+2)x=0
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
x2+x−6+(−y−2)x=0
Simplify
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Evaluate
x+(−y−2)x
Collect like terms by calculating the sum or difference of their coefficients
(1−y−2)x
Subtract the numbers
(−1−y)x
x2+(−1−y)x−6=0
Move the constant to the right side
x2+(−1−y)x=0−(−6)
Add the terms
x2+(−1−y)x=6
Add the same value to both sides
x2+(−1−y)x+41+2y+y2=6+41+2y+y2
Evaluate
x2+(−1−y)x+41+2y+y2=425+2y+y2
Evaluate
(x−21+y)2=425+2y+y2
Take the root of both sides of the equation and remember to use both positive and negative roots
x−21+y=±425+2y+y2
Simplify the expression
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Evaluate
425+2y+y2
To take a root of a fraction,take the root of the numerator and denominator separately
425+2y+y2
Simplify the radical expression
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Evaluate
4
Write the number in exponential form with the base of 2
22
Reduce the index of the radical and exponent with 2
2
225+2y+y2
x−21+y=±225+2y+y2
Separate the equation into 2 possible cases
x−21+y=225+2y+y2x−21+y=−225+2y+y2
Calculate
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Evaluate
x−21+y=225+2y+y2
Move the expression to the right-hand side and change its sign
x=225+2y+y2+21+y
Write all numerators above the common denominator
x=225+2y+y2+1+y
x=225+2y+y2+1+yx−21+y=−225+2y+y2
Solution
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Evaluate
x−21+y=−225+2y+y2
Move the expression to the right-hand side and change its sign
x=−225+2y+y2+21+y
Write all numerators above the common denominator
x=2−25+2y+y2+1+y
x=225+2y+y2+1+yx=2−25+2y+y2+1+y
Show Solution
Rewrite the equation
Rewrite in polar form
r=sin(2θ)−2cos2(θ)−cos(θ)+25cos2(θ)−12sin(2θ)r=−sin(2θ)−2cos2(θ)cos(θ)+25cos2(θ)−12sin(2θ)
Evaluate
y=xx2+x−6−2
Multiply both sides of the equation by LCD
yx=(xx2+x−6−2)x
Simplify the equation
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Evaluate
(xx2+x−6−2)x
Apply the distributive property
xx2+x−6×x−2x
Simplify
x2+x−6−2x
Subtract the terms
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Evaluate
x−2x
Collect like terms by calculating the sum or difference of their coefficients
(1−2)x
Subtract the numbers
−x
x2−x−6
yx=x2−x−6
Move the expression to the left side
yx−x2+x=−6
To convert the equation to polar coordinates,substitute rcos(θ) for x and rsin(θ) for y
sin(θ)×rcos(θ)×r−(cos(θ)×r)2+cos(θ)×r=−6
Factor the expression
(sin(θ)cos(θ)−cos2(θ))r2+cos(θ)×r=−6
Simplify the expression
(21sin(2θ)−cos2(θ))r2+cos(θ)×r=−6
Subtract the terms
(21sin(2θ)−cos2(θ))r2+cos(θ)×r−(−6)=−6−(−6)
Evaluate
(21sin(2θ)−cos2(θ))r2+cos(θ)×r+6=0
Solve using the quadratic formula
r=sin(2θ)−2cos2(θ)−cos(θ)±cos2(θ)−4(21sin(2θ)−cos2(θ))×6
Simplify
r=sin(2θ)−2cos2(θ)−cos(θ)±25cos2(θ)−12sin(2θ)
Separate the equation into 2 possible cases
r=sin(2θ)−2cos2(θ)−cos(θ)+25cos2(θ)−12sin(2θ)r=sin(2θ)−2cos2(θ)−cos(θ)−25cos2(θ)−12sin(2θ)
Solution
r=sin(2θ)−2cos2(θ)−cos(θ)+25cos2(θ)−12sin(2θ)r=−sin(2θ)−2cos2(θ)cos(θ)+25cos2(θ)−12sin(2θ)
Show Solution