Question
Function
Find the vertex
Find the axis of symmetry
Rewrite in vertex form
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(−25,473)
Evaluate
y=−x2−5x+12
Find the x-coordinate of the vertex by substituting a=−1 and b=−5 into x = −2ab
x=−2(−1)−5
Solve the equation for x
x=−25
Find the y-coordinate of the vertex by evaluating the function for x=−25
y=−(−25)2−5(−25)+12
Calculate
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Evaluate
−(−25)2−5(−25)+12
Multiply the numbers
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Evaluate
−5(−25)
Multiplying or dividing an even number of negative terms equals a positive
5×25
Multiply the numbers
25×5
Multiply the numbers
225
−(−25)2+225+12
Evaluate the power
−425+225+12
Reduce fractions to a common denominator
−425+2×225×2+2×212×2×2
Multiply the numbers
−425+425×2+2×212×2×2
Multiply the numbers
−425+425×2+412×2×2
Write all numerators above the common denominator
4−25+25×2+12×2×2
Multiply the numbers
4−25+50+12×2×2
Multiply the terms
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Evaluate
12×2×2
Multiply the terms
24×2
Multiply the numbers
48
4−25+50+48
Add the numbers
473
y=473
Solution
(−25,473)
Show Solution
Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
y=−x2−5x+12
To test if the graph of y=−x2−5x+12 is symmetry with respect to the origin,substitute -x for x and -y for y
−y=−(−x)2−5(−x)+12
Simplify
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Evaluate
−(−x)2−5(−x)+12
Multiply the numbers
−(−x)2+5x+12
Rewrite the expression
−x2+5x+12
−y=−x2+5x+12
Change the signs both sides
y=x2−5x−12
Solution
Not symmetry with respect to the origin
Show Solution
Identify the conic
Find the standard equation of the parabola
Find the vertex of the parabola
Find the focus of the parabola
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(x+25)2=−(y−473)
Evaluate
y=−x2−5x+12
Swap the sides of the equation
−x2−5x+12=y
Move the constant to the right-hand side and change its sign
−x2−5x=y−12
Multiply both sides of the equation by −1
(−x2−5x)(−1)=(y−12)(−1)
Multiply the terms
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Evaluate
(−x2−5x)(−1)
Use the the distributive property to expand the expression
−x2(−1)−5x(−1)
Multiplying or dividing an even number of negative terms equals a positive
x2−5x(−1)
Multiply the numbers
x2+5x
x2+5x=(y−12)(−1)
Multiply the terms
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Evaluate
(y−12)(−1)
Apply the distributive property
y(−1)−12(−1)
Multiplying or dividing an odd number of negative terms equals a negative
−y−12(−1)
Simplify
−y+12
x2+5x=−y+12
To complete the square, the same value needs to be added to both sides
x2+5x+425=−y+12+425
Use a2+2ab+b2=(a+b)2 to factor the expression
(x+25)2=−y+12+425
Add the numbers
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Evaluate
12+425
Reduce fractions to a common denominator
412×4+425
Write all numerators above the common denominator
412×4+25
Multiply the numbers
448+25
Add the numbers
473
(x+25)2=−y+473
Solution
(x+25)2=−(y−473)
Show Solution
Solve the equation
Solve for x
x=273−4y−5x=−273−4y+5
Evaluate
y=−x2−5x+12
Swap the sides of the equation
−x2−5x+12=y
Move the expression to the left side
−x2−5x+12−y=0
Move the constant to the right side
−x2−5x=0−(12−y)
Add the terms
−x2−5x=−12+y
Evaluate
x2+5x=12−y
Add the same value to both sides
x2+5x+425=12−y+425
Evaluate
x2+5x+425=473−4y
Evaluate
(x+25)2=473−4y
Take the root of both sides of the equation and remember to use both positive and negative roots
x+25=±473−4y
Simplify the expression
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Evaluate
473−4y
To take a root of a fraction,take the root of the numerator and denominator separately
473−4y
Simplify the radical expression
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Evaluate
4
Write the number in exponential form with the base of 2
22
Reduce the index of the radical and exponent with 2
2
273−4y
x+25=±273−4y
Separate the equation into 2 possible cases
x+25=273−4yx+25=−273−4y
Calculate
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Evaluate
x+25=273−4y
Move the constant to the right-hand side and change its sign
x=273−4y−25
Write all numerators above the common denominator
x=273−4y−5
x=273−4y−5x+25=−273−4y
Solution
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Evaluate
x+25=−273−4y
Move the constant to the right-hand side and change its sign
x=−273−4y−25
Subtract the terms
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Evaluate
−273−4y−25
Write all numerators above the common denominator
2−73−4y−5
Use b−a=−ba=−ba to rewrite the fraction
−273−4y+5
x=−273−4y+5
x=273−4y−5x=−273−4y+5
Show Solution
Rewrite the equation
Rewrite in polar form
r=2cos2(θ)−sin(θ)−5cos(θ)+1+72cos2(θ)+5sin(2θ)r=−2cos2(θ)sin(θ)+5cos(θ)+1+72cos2(θ)+5sin(2θ)
Evaluate
y=−x2−5x+12
Move the expression to the left side
y+x2+5x=12
To convert the equation to polar coordinates,substitute rcos(θ) for x and rsin(θ) for y
sin(θ)×r+(cos(θ)×r)2+5cos(θ)×r=12
Factor the expression
cos2(θ)×r2+(sin(θ)+5cos(θ))r=12
Subtract the terms
cos2(θ)×r2+(sin(θ)+5cos(θ))r−12=12−12
Evaluate
cos2(θ)×r2+(sin(θ)+5cos(θ))r−12=0
Solve using the quadratic formula
r=2cos2(θ)−sin(θ)−5cos(θ)±(sin(θ)+5cos(θ))2−4cos2(θ)(−12)
Simplify
r=2cos2(θ)−sin(θ)−5cos(θ)±1+72cos2(θ)+5sin(2θ)
Separate the equation into 2 possible cases
r=2cos2(θ)−sin(θ)−5cos(θ)+1+72cos2(θ)+5sin(2θ)r=2cos2(θ)−sin(θ)−5cos(θ)−1+72cos2(θ)+5sin(2θ)
Solution
r=2cos2(θ)−sin(θ)−5cos(θ)+1+72cos2(θ)+5sin(2θ)r=−2cos2(θ)sin(θ)+5cos(θ)+1+72cos2(θ)+5sin(2θ)
Show Solution