begin{arrayl2x+3y=12x-y=1endarray.

Frequently Asked Questions

• Solve using the substitution method of $\{\begin{array}{l}2x+3y=12\\ x-y=1\end{array}$

  

  $$\left(x,y\right)=\left(3,2\right)$$

• Solve using the elimination method of $\{\begin{array}{l}2x+3y=12\\ x-y=1\end{array}$

  

  $$\left(x,y\right)=\left(3,2\right)$$

• Solve using the Gauss-Jordan method of $\{\begin{array}{l}2x+3y=12\\ x-y=1\end{array}$

  

  $$\left(x,y\right)=\left(3,2\right)$$

• Solve using the Cramer's rule of $\{\begin{array}{l}2x+3y=12\\ x-y=1\end{array}$

  

  $$\left(x,y\right)=\left(3,2\right)$$

• Determine whether lines are parallel, perpendicular, or neither of $\{\begin{array}{l}2x+3y=12\\ x-y=1\end{array}$

  

  $$\text{Neither parallel nor perpendicular}$$